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Match the reactions given in column - I with the nature of the reaction/products given in column - II Column - I Column - II A MnO 4 2 - aq + 4 H + aq ⟶ p Show disproportionation B Cu 2 + aq + I - aq ⟶ q Redox reaction C CrO 4 2 aq + H + aq ⟶ r One of the products is diamagnetic D Fe 3 + aq + Fe CN 6 4 - aq ⟶ s One of the products has metal-oxygen-metal bond/linkage

Options

  1. AA → p, q, r ; B → q, r ; C → r, s ; D → r
  2. BA → p, q, ; B → q, r ; C → r, s, s ; D → r
  3. CA → p, q, r ; B → q, r ; C → r, s ; D → s
  4. DA → p, q, r ; B → q, r, s ; C → r, s ; D → s

Correct answer

A. A → p, q, r ; B → q, r ; C → r, s ; D → r

Step-by-step solution

When oxidation and reduction take place on the same element of a compound is called a disproportionation reaction. The chemical reaction which involves transfer of electrons from one chemical substance to another is called a redox reaction. A species which has no unpaired electron is called as diamagnetic. (A) Mn VI O 4 2 - + 4 H + ⟶ 2 Mn VII O 4 - + Mn IV O 2 + 2 H 2 O The oxidation state of Mn is changing from + 6   to   + 7   and   + 6   to   + 4 . Hence it is a disproportion

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