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Identify the oxidation states of Mn , when MnO ₄²⁻ ion undergoes disproportionation reaction under acidic medíum.

Options

  1. A+2,+7
  2. B+2,+5
  3. C+4,+4
  4. D+7,+4

Correct answer

D. +7,+4

Step-by-step solution

The disproportionation reaction for MnO ₄²⁻ occurs as follows : 3 +6 MnO ₄²⁻ +4 H ⁺ +4 MnO ₂ +2 +7 M n MO ₄⁻+2 H ₂ O Hence, MnO ₄²⁻ is oxidised to MnO ₄⁻ and reduced to MnO ₂ . Thus, oxidation state of Mn when MnO ₄²⁻ undergoes disproportionation reaction under acidic medium are +7 and +4 . Hence option (d) is the correct answer.

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