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Why does the following reaction occur ? XeO 6 4 - aq + 2 F - aq + 6 H + aq ⟶ XeO 3 g + F 2 g + 3 H 2 O l ⁡ What conclusion about the compound Na 4 XeO 6 (of which XeO 6 4 - is a part) can be drawn from the reaction ? select any one of the correct choice.

Options

  1. A[ XeO 6 ] 4 - is a stronger oxidising agent than F 2
  2. BF 2 is stronger oxidising agent than [ XeO 6 ] 4 -
  3. CXe is an inert gas
  4. DIt is non redox reaction

Correct answer

A. [ XeO 6 ] 4 - is a stronger oxidising agent than F 2

Step-by-step solution

Oxidation number change for the compounds in the reaction. Xe + 8 O 6 4 - aq ⁡ + 2 F ⁡ - 1 - 1 aq ⁡ + 6 H + aq ⁡ ⟶ Xe + 6 O 3 g + F 2 0 + 3 H 2 O l ⁡ In the above reaction: Oxidation number of Xe in XeO 6 4 - decreases from + 8 to + 6 in XeO 3 Oxidation number of F increases from - 1 (in F - ) to zero (in F 2 ). Hence, XeO 6 4 - or Na 4 XeO 6 is reduced and F - is oxidised. This reaction occurs because Na 4 XeO 6 or XeO 6 4 - is a stronger oxidising agent than fluorine.

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