The Henry's law constant for the solubility of N ₂ gas in water at 298 ~K is 1 10⁺⁵ ~atm . The mole fraction of air is 0.8 . The number of moles of N ₂ from air dissolved in 10 moles of water at 298 ~K and 5 atm pressure is

Step-by-step solution

At total pressure 5 ~atm , the partial pressure of N ₂=5 0.8=4 ~atm According to Henry's Law, P _ N ₂ = K _ H x _ N ₂ ( x _ N ₂ ) is the mole fraction of nitrogen gas dissolved in water. or, x _ N ₂ = 4 ~atm 1 10^5 ~atm or, x _ N ₂ =4 10⁻⁵ aligned & n _ N ₂ n _ N ₂ + n _ H ₂ O n _ N ₂ n _ H ₂ O =4 10⁻⁵ [ since n _ H ₂ O n _ N ₂ ] & n _ N ₂ =4 10⁻⁵ 10=4 10⁻⁴ ~mol aligned