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What will be the molar mass of solute if vapour pressure of pure benzene is 450 ~mm Hg when 1 5 ~g of non volatile solute is added to 30 ~g of benzene? (Vapour pressure of solution =400 ~mm Hg , atomic mass C =12, H =1 )

Options

  1. A1.35 1 ~g ~mol ⁻¹
  2. B2.26 1 ~g ~mol ⁻¹
  3. CX ₃ .28 4 ~g ~mol ⁻¹
  4. D4. 30 0 ~g ~mol ⁻¹

Correct answer

A. 1.35 1 ~g ~mol ⁻¹

Step-by-step solution

P ⁰=450 ~mm ~Hg , P =400 ~mm ~Hg , M ₁=78 ~g ~mol ⁻¹ (molar mass of benzene), W ₁=30 ~g , ~W ₂=1.5 ~g , M ₂=? M ₂= W ₂ M ₁ ~W ₁ P ₀ ( P ₀- P ) M ₂= 1.5 78 30 450 (450-400) =35.1 ~g ~mol ⁻¹

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