At 293 ~K , the Henry law constant in water for N ₂ and O ₂ are 76.48 k bar and 34.86 k bar respectively. What is the ratio of mole fractions of N ₂ and O ₂ in water? (Assume partial pressures of N ₂ and O ₂ same at 293 ~K )

Step-by-step solution

According to Henry's law :- P = xK _ H For N ₂ :- P _ N ₂ = x _ N ₂ ~K _ H ( N ₂ ) For O ₂ :- P _ O ₂ = x _ O ₂ ~K _ H ( O ₂ ) We have, P _ N ₂ = P _ O ₂ , ~K _ H ( N ₂ )=76.48 k bar, K _ H ( O ₂ )=3486 k bar aligned & x _ N ₂ x _ O ₂ = ( P _ N ₂ ~K _ H ( N ₂ ) ) ( P _ O ₂ ~K _ H ( O ₂ ) ) = P N ₂ ~K _ H ( N ₂ ) K _ H ( O ₂ ) P O ₂ & = K _ H ( O ₂ ) K _ H ( N ₂ ) = 34.86 76.48 =0.45 aligned