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When 2 . 44 grams of benzoic acid C 6 H 5 COOH dissolved in 25 grams of benzene, it shows depression of freezing point equal to 2 . 2   K . Molal depression constant of benzene is 5 . 0   K   kg   mol - 1 . What is the percentage association of acid, if it forms dimer in solution?

Options

  1. A50 %
  2. B90%
  3. C95 %
  4. D77%

Correct answer

B. 90%

Step-by-step solution

Given , W B = 2 . 44 g   ,   K f = 5   K   k g   m o l - 1 W A   = 25 g   ,   ∆ T f     = 2 . 2 K   W B = 2 . 44 g   ,   K f = 5   K   k g   m o l - 1 W A   = 25 g   ,   ∆ T f     = 2 . 2 K   N o w   , ∆ T f   =   K f   × W B M B   × 1000 W A M B = 5 × 2 . 44 × 1000 2 . 2 × 25 = 221 . 8 g / m o l 2 C 6 H 5 C O O H   ⇔ C 6 H 5 C

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