The elevation in boiling point, when 13.44 g of freshly prepared CuCl 2 are added to one kilogram of water, is. [Some useful data, k b = 0.52 kg K mol -1 , molecular weight of CuCl 2 = 134.4 g].

Step-by-step solution

CuCl 2 aq → Cu aq 2 + + 2 Cl aq - with complete dissociation in aqueous solution. Van't Hoff factor = 3 = i Δ T b = i K b · m = 3 × 0.52 × 13.44 134.4 1000 1000 Moles of ClCl 2 = 1 3 · 4 4 1 3 4 · 4 = 0 · 1 mole = 3 × 0.52 × 0.1 = 0.156 K ≈ 0.16 K