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If the density of a 2 M solution of ethylene glycol in water is 1 . 11 g / ml , the molality (in m ) of the solution is approximately

Options

  1. A1 . 92
  2. B1 . 57
  3. C2 . 02
  4. D2 . 15

Correct answer

C. 2 . 02

Step-by-step solution

Density of solution = 1 . 11   gml - 1 Molarity of solution = 2 M Density is the amount of x   g of solution in 1000 ml of solution. Mass of solution = density   × volume = 1 . 11 × 1000 = 1110 g Molality is equal to the number of moles of solute present in 1000   g of solution. Number of moles of solute = 2   mole Molar mass of ethylene glycol= 62   g / mol Mass of solute = Mole × molar   mass = 2 × 62 = 124   g Mass of the solvent = 1110 - 124 = 986 g Mo

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