The molality and molarity of a solution of a glucose in water which is labelled as 10 %(w / w) are respectively (density of solution .=1.2 ~g ~mL ⁻¹ )

Step-by-step solution

Mass by mass percentage is the mass of solute dissolved in 100 ~g of the solution. Mass of solution =100 ~g Mass of glucose =10 ~g Mass of solvent =90 ~g Molar mass of glucose ( C ₆ H ₁₂ O ₆ )=12 6+1 12+16 6=180 ~g / mol gathered Molality = Mass of solute Molar mass of solute 1000 Mass of solvent (in g) gathered = 10 180 1000 90 =0.617 ~m Also, volume of solution = Mass of solution Density of solution = 100 ~g 1.2 ~g / mL =83.33 ~mL Molarity = 10 180 1000 83.33 =0.67 M