99 Percentile Qs Bank for JEE MainChemistrySolutions
Calculate the approximate T_b (in K) for 0.001 molal KCl solution, if its van't-Hoff factor is 1.98 [K_b . of water is .0.52 ~K ~kg ~mol ⁻¹ ]
Options
- A1.03
- B1.03 10⁻³
- C1.03 10⁻⁵
- D1.03 10⁻¹
Correct answer
B. 1.03 10⁻³
Step-by-step solution
We know that T_b=i K_b m ( T_b=i . K_b m ) where, T_b= elivation in boiling point (to time) aligned i & = van't-Hoff factor (1.98) K_b & = molal elevation constant (0.52) m & = molality (0.001 ~m ) T_b & =1.98 0.52 0.001=0.0010296 T_b & =1.03 10⁻³ aligned