The vapour pressure in mm of Hg , of an aqueous solution obtained by adding 18 ~g of glucose ( C ₆ H ₁₂ O ₆ ) to 180 ~g of water at 100^ C is

Step-by-step solution

According to Raoult's law p^ -p_s p^ = n₂ n₁+n₂ where, p^ = vapour pressure of pure water at 100^ C =760 mmHg . p_s= vapour pressure of solution at 100^ C aligned & n₂= moles of solute = W₂ M₂ = 18 180 =0.1 ~mol & n₁= moles of solvent = W₁ M₁ = 180 18 =10 ~mol aligned By putting these values in the formula p^ -p_s p^ = 0.1 10+0.1 or aligned 10.1 (p^ -p_s ) & =0.1 p^ 10 p^ & =10.1 p_s p_s= 10 760 10.1 & =752.4 mmHg . aligned