Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainMathematicsComplex Number

The number of solutions for z^3+ z =0 , is

Options

  1. A5
  2. B1
  3. C2
  4. D3

Correct answer

A. 5

Step-by-step solution

Given, z^3+ z =0 Let z=x+i y aligned & (x+i y)^3+x-i y=0 & x^3+(i y)^3+3 x^2 i y+3 x(i y)^2+x-i y=0 & x^3-y^3 i+3 x^2 y i-3 x y^2+x-i y=0 & (x^3-3 x y^2+x )+ (-y^3+3 x^2 y-y ) i=0 aligned On equating real and imaginary parts, we get aligned & x^3-3 x y^2+x=0 & or -y^3+3 x^2 y-y=0 & x (x^2-3 y^2+1 )=0 & or -y (y^2-3 x^2+1 )=0 & x=0 and x^2-3 y^2+1=0 & or y=0 and y^2-3 x^2+1=0 & Now, & x^3-3 y^2+1=y^2-3 x^2+1 & 4 x^2=4 y^2 & x= y & y^2-3 y^2+1=0 & 2 y^2=1 y= 1 2 & x= 1 2 & aligned Hence, their solutions are (0,0) and

Practice Complex Number on Quantrex Academy →

More from Complex Number

The number of values of z C , satisfying the equations |z-(4+8i)|= 10 and |z-(3+5i)|+|z-(5+11i)|=4 5 , is: 2026Let S = z C : z^2 + 6 ,iz - 3 = 0 . Then _ z S z^8 is equal to : 2026Let the set of all values of k R such that the equation z( z + 2 + i) + k(2 + 3i) = 0 , z C , has at least one solution, be the interval [ , ] . Then 9( + ) is equal to: 2026Let z₁, z₂ C be the distinct solutions of the equation z^2 + 4z - (1 + 12i) = 0 . Then |z₁|^2 + |z₂|^2 is equal to : 2026Let S= z C : z^2+4z+16=0 . Then _ z S |z+ 3 i|^2 is equal to: 2026Let z be a complex number such that |z+2| = |z-2| and ( z+3 z-i ) = 4 . Then |z|^2 is equal to: 2026Let the circles C₁ : |z| = r and C₂ : |z - 3 - 4i| = 5 , z C , be such that C₂ lies within C₁ . If z₁ moves on C₁ , z₂ moves on C₂ and |z₁ - z₂| = 2 , then |z₁ - z₂| is equal to: 2026Let x and y be real numbers such that 50 ( 2x 1+3i - y 1-2i ) = 31 + 17i , i = -1 . Then the value of 10(x - 3y) is : 2026 Full Complex Number list All 99 Percentile Qs Bank for JEE Main PYQs