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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Chemistry
Chapter
General Principles and Processes of Isolation of Metals

JEE Main 2022 · 25 June · Morning Shift · Chemistry · General Principles and Processes of Isolation of Metals

Leaching of gold with dilute aqueous solution of NaCN in presence...

Leaching of gold with dilute aqueous solution of NaCNNaCN in presence of oxygen gives complex \left[A\right],whichonreactionwithzincformstheelementalgoldandanothercomplex[B], which on reaction with zinc forms the elemental gold and another complex \left[B\right]. \left[A\right]and[B]and \left[B\right], respectively are

Options

  1. A{\left[Au{\left(CN\right)}_{2}\right]}^{-} and [Zn(CN)4]2−{\left[Zn{\left(CN\right)}_{4}\right]}^{2 -}
  2. B{\left[Au{\left(CN\right)}_{4}\right]}^{-} and [Zn(CN)2(OH)2]2−{\left[Zn{\left(CN\right)}_{2}{\left(OH\right)}_{2}\right]}^{2 -}
  3. C{\left[Au{\left(CN\right)}_{2}\right]}^{-} and [Zn(OH)4]2−{\left[Zn{\left(OH\right)}_{4}\right]}^{2 -}
  4. D[Au(CN)4]2−{\left[Au{\left(CN\right)}_{4}\right]}^{2 -} and [Zn(CN)6]4−{\left[Zn{\left(CN\right)}_{6}\right]}^{4 -}

Correct answer

A. {\left[Au{\left(CN\right)}_{2}\right]}^{-} and [Zn(CN)4]2−{\left[Zn{\left(CN\right)}_{4}\right]}^{2 -}

Step-by-step solution

Extraction of gold is carried out by leaching process.

Sodium cyanide (NaCN)( NaCN ) has been used as leaching reagent for gold.

Metal is converted into the soluble cyanide complex on reaction with sodium cyanide.

4Au+8CN−+2H2O+O2→4[Au(CN)2]−X+4OH−4Au + 8 {CN}^{-} + 2{H}_{2}O + {O}_{2} \to 4\mathop{[ Au ( CN{)}_{2}{]}^{-}}_{X} + 4{OH}^{-}

Silver is later recovered by displacement with ZnZn.

2[Au(CN)2]−+Zn→Displacement[Zn(CN)4]2−Y+2Au2{\left[Au{\left(CN\right)}_{2}\right]}^{-} + Zn\overset{\text{Displacement}}{\to}\mathop{{\left[Zn{\left(CN\right)}_{4}\right]}^{2 -}}_{Y} + 2Au

XandYX\text{and}Y are [Au(CN)2]−[ Au ( CN{)}_{2}{]}^{-} and [Zn(CN)4]2−[ Zn ( CN{)}_{4}{]}^{2-}, respectively.

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