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99 Percentile Qs Bank for JEE MainMathematicsLimits

lim x → - ∞ 3 x - x x - 2 x - lim x → 0 log 1 + x 3 sin 3 x =

Options

  1. A1
  2. B1 3
  3. C4 3
  4. D0

Correct answer

B. 1 3

Step-by-step solution

Consider, lim x → - ∞ 3 x - x x - 2 x = lim x → - ∞ 3 - x - x - x - 2 x ∴ x → - ∞ , x = - x = lim x → - ∞ - 3 x - x - x - 2 x = lim x → - ∞ - 4 x - 3 x = 4 3 lim x → 0 log 1 + x 3 sin 3 x = lim x → 0 log 1 + x 3 x 3 sin 3 x x 3 = 1 Now lim x → - ∞ 3 x - x x - 2 x - lim x → 0 log 1 + x 3 sin 3 x = 4 3 - 1 = 4 - 3 3 = 1 3

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