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JEE Limits PYQs with Solutions

497 previous year questions from Limits (JEE Main & Advanced Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

497 questionsMathematics2002–2026Answers + solutions

About Limits PYQs

Limits has 497 previous year questions in the Quantrex Academy JEE Main & Advanced Mathematics bank. The 220 questions in this list come from JEE Main (145), NTA Abhyas JEE Main (44) and JEE Advanced (31), spanning 2002 to 2026. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

  • 2026: 9
  • 2025: 15
  • 2024: 26
  • 2023: 11
  • 2022: 16
  • 2021: 19
  • 2020: 55
  • 2019: 15
  • 2018: 4
  • 2017: 3
  • 2016: 8
  • 2015: 4

Limits questions with solutions

1

Let _ x → 2 (( (x-2))(rx^2 + (p-2)x - 2p))/((x-2)^2) = 5 for some r, p ∈ ℝ . If the set of all possible values of q , such that the roots of the equation rx^2 - px + q = 0 lie in

JEE Main 2026 Solution
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2

The value of _ x → 0 ((x^2 ^2 x)/(x^2 - ^2 x)) is:

JEE Main 2026 Solution
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3

Let f(x) = _ y → 0 ((1 - (xy)) (xy))/(y^3) . Then the number of solutions of the equation f(x) = x , x ∈ R is :

JEE Main 2026 Solution
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4

The product of all possible values of α , for which _ x → 0 ((1 - (α x) ((α+1)x) ((α+2)x))/( ^2((α+1)x))) = 2 , is:

JEE Main 2026 Solution
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5

If _ x → 2 (x^3 - 5x^2 + ax + b) ( x-1 - 1) _e(x-1) = m , then a + b + m is equal to :

JEE Main 2026 Solution
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6

The value of _ x arrow 0 _ e ( (e x) · (e^ 2 x) · … · (e^ 10 x)) e^ 2 -e^ 2 x is equal to

JEE Main 2026 Solution
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7

If _ x arrow 0 e^ (a-1) x +2 ~b x+(c-2) e^ -x x x- _ e (1+x) =2 , then a^ 2 +b^ 2 +c^ 2 is equal to :

JEE Main 2026 Solution
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8

Let [·] denote the greatest integer function and f(x)= _ n arrow ∞ 1 n^ 3 ∑_ k=1 ^ n [ k^ 2 3^ x ] . Then 12 ∑_ j=1 ^ ∞ f(j) is equal to \_\_\_\_ .

JEE Main 2026 Solution
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9

Let f: R arrow(0, ∞) be a twice differentiable function such that f(3)=18, f^ (3)=0 and f^ (3)=4 . Then _ x arrow 1 ( _ e ((f(2+x))/(f(3)))^ 18 (x-1)^ 2 ) is equal to :

JEE Main 2026 Solution
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10

Let α and β be the real numbers such that _ x arrow 0 (1)/(x^3)((α)/(2) ∫_0^x (1)/(1-t^2) d t+β x x)=2 . Then the value of α+β is _______

JEE Advanced 2025 Solution
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11

Let x_0 be the real number such that e^ x_0 +x_0=0 . For a given real number α , define g(x)=(3 x e^x+3 x-α e^x-α x)/(3(e^x+1)) for all real numbers x . Then which one of the

JEE Advanced 2025 Solution
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12

Given below are two statements : Statement I : _ x arrow 0 ( ^ -1 x+ _e (1+x)/(1-x) -2 x x^5 )=(2)/(5) Statement II : _ x arrow 1 (x^ 2 1-x )= 1 e^2 In the light of the above

JEE Main 2025 Solution
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13

If the function f(x)=( ( x)- ( x))/( x- x) is continuous at x=0 , then f(0) is equal to ________

JEE Main 2025 Solution
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14

_ x arrow 0^ + (5(x)^ (1)/(3) ) _e(1+3 x^2) ( ^ -1 3 x )^2(e^ 5(x)^ (4)/(3) -1) is equal to

JEE Main 2025 Solution
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15

If _ x arrow 1^ + ((x-1)(6+λ (x-1))+μ (1-x))/((x-1)^3)=-1 , where λ, μ ∈ ℝ , then λ+μ is equal to

JEE Main 2025 Solution
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16

If Lim_ x arrow 0 (( x)/(x))^ (1)/(x^2) =p , then 96 _e p is equal to ______

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17

If _ x arrow 0 ( (2 x)+a (4 x)-b)/(x^4) is finite, then (a+b) is equal to :

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18

For α, β, γ, ∈ R , if _ x arrow 0 x^2 α x+(γ-1) e^ x^2 2 x-β x =3 , then β+γ-α is equal to:

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19

If _ t arrow 0 (∫_0^1(3 x+5)^ t d x)^ (1)/(t) = α 5 e ((8)/(5))^ (2)/(3) , then α is equal to ________

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20

Let [t] be the greatest integer less than or equal to t. Then the least value of \( p ∈ N \) for which \( _ x arrow 0^ + ( x ([(1)/(x)]+[(2)/(x)]+…+[ p x ])- x^2

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21

Let f(x)= _ n arrow ∞ ∑_ r=0 ^ n ( (x / 2^ r+1 )+ ^3(x / 2^ r+1 ) 1- ^2(x / 2^ r+1 ) ) . Then _ x arrow 0 e^x-e^ f(x) (x-f(x)) is equal to

JEE Main 2025 Solution
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22

_ x arrow 0 cosec x( 2 ^2 x+3 x - ^2 x+ x+4 ) is:

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23

_ x arrow ∞ (2 x^2-3 x+5)(3 x-1)^ (x)/(2) (3 x^2+5 x+4) (3 x+2)^x is equal to :

JEE Main 2025 Solution
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24

If _ x arrow ∞ (( e 1-e )( 1 e -(x)/(1+x)))^x=α , then the value of _ e α 1+ _ e α equals :

JEE Main 2025 Solution
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25

Let k ∈ ℝ . If _ x arrow 0^+ ( ( k x)+ x+x)^ (2)/(x) =e^6 , then the value of k is

JEE Advanced 2024 Solution
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26

Let S be the set of all (α, β) ∈ ℝ × ℝ such that _ x arrow ∞ (x^2)( _e x)^α ((1)/(x^2)) x^ α β ( _e(1+x))^β =0 . Then which of the following is (are) correct?

JEE Advanced 2024 Solution
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27

Let the function f:[1, ∞) arrow ℝ be defined by f(t)=\ array cc (-1)^ n+1 2, & if t=2 n-1, n ∈ ℕ , ((2 n+1-t))/(2) f(2 n-1)+ ((t-(2 n-1)))/(2) f(2 n+1), & if 2 n-1 < t < 2 n+1, n

JEE Advanced 2024 Solution
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28

Let f(x) be a continuously differentiable function on the interval (0, ∞) such that f(1)=2 and t arrow x t^ 10 f(x)-x^ 10 f(t) t^9-x^9 =1 for each x>0 . Then, for all x>0, f(x) is

JEE Advanced 2024 Solution
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29

_ x arrow (π)/(2) ( ∫_ x^3 ^ (π / 2)^3 ( (2 t^ 1 / 3 )+ (t^ 1 / 3 )) d t (x-(π)/(2))^2 ) is equal to

JEE Main 2024 Solution
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30

_ x arrow 0 e-(1+2 x)^ (1)/(2 x) x is equal to

JEE Main 2024 Solution
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31

Let _ n arrow ∞ ( n n^4+1 - 2 n (n^2+1) n^4+1 + n n^4+16 - 8 n (n^2+4) n^4+16 . .+…+ n n^4+n^4 - 2 n · n^2 (n^2+n^2) n^4+n^4 ) be (π)/(k) , using only the principal values of the

JEE Main 2024 Solution
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32

If α= _ x arrow 0^ + ( e^ x -e^ x x - x ) and β= _ x arrow 0 (1+ x)^ (1)/(2) x are the roots of the quadratic equation a x^2+b x- e =0 , then 12 _ e (a+b) is equal to__________

JEE Main 2024 Solution
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33

The value of _ x arrow 0 2 ( 1- x 2 x [3] 3 x … … [10] 10 x x^2 )is

JEE Main 2024 Solution
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34

_ n arrow ∞ ((1^2-1)(n-1)+(2^2-2)(n-2)+⋯+((n-1)^2-(n-1)) · 1)/((1^3+2^3+⋯ ⋯+n^3)-(1^2+2^2+⋯ ⋯+n^2)) is equal to :

JEE Main 2024 Solution
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35

Let f:(-∞, ∞)-\ 0\ arrow ℝ be a differentiable function such that f^ (1)= _ a arrow ∞ a^2 f((1)/(a)) . Then _ a arrow ∞ (a(a+1))/(2) ^ -1 ((1)/(a))+a^2-2 _e a is equal to

JEE Main 2024 Solution
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36

Let a>0 be a root of the equation 2 x^2+x-2=0 . If _ x arrow 1 a 16(1- (2+x-2 x^2)) (1-a x)^2 =α+β 17 , where α, β ∈ Z , then α+β is equal to_______

JEE Main 2024 Solution
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37

Let f be a differentiable function in the interval (0, ∞) such that f(1)=1 and _ t arrow x (t^2 f(x)-x^2 f(t))/(t-x)=1 for each x>0 . Then 2 f(2)+3 f(3) is equal to _______

JEE Main 2024 Solution
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38

Let f(x)=∫_0^x(t+ (1-e^ )) d t, x ∈ ℝ . Then, _ x arrow 0 (f(x))/(x^3) is equal to

JEE Main 2024 Solution
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39

If _ x arrow 1 (5 x+1)^ 1 / 3 -(x+5)^ 1 / 3 (2 x+3)^ 1 / 2 -(x+4)^ 1 / 2 = m 5 n(2 n)^ 2 / 3 , where gcd(m, n)=1 , then 8 ~m+12 n is equal to______

JEE Main 2024 Solution
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40

Let f(x) = \ array ll x - 1, x is even , 2x, x is odd , array x ∈ N . If for some a ∈ N, f(f(f(a))) = 21 , then _ x → a ^ - \ |x| ^ 3 a - [(x)/(a)]\ , where [t] denotes the

JEE Main 2024 Solution
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41

Let \ x\ denote the fractional part of x and f(x) = ^ - 1 (1 - \ x\ ^ 2 ) ^ - 1 (1 - \ x\ ) \ x\ - \ x\ ^ 3 , x ≠ 0 . If LandR respectively denotes the left hand limit and the

JEE Main 2024 Solution
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42

Let f:ℝ→ (0, ∞) be strictly increasing function such that _ x → ∞ (f(7x))/(f(x)) = 1 . Then, the value of _ x → ∞ [(f(5x))/(f(x)) - 1] is equal to

JEE Main 2024 Solution
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43

If _ x → 0 a x ^ 2 e ^ x - b _ e (1 + x) + cx e ^ - x x ^ 2 sinx = 1 , then 16( a ^ 2 + b ^ 2 + c ^ 2 ) is equal to ______.

JEE Main 2024 Solution
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44

_ x → 0 e ^ 2|sinx| - 2|sinx| - 1 x ^ 2

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45

Let a be the sum of all coefficients in the expansion of ( 1 – 2x + 2 x ^ 2 ) ^ 2023 ( 3 - 4 x ^ 2 + 2 x ^ 3 ) ^ 2024 and b = _ x → 0 ( ∫ _ 0 ^ x log(1 + t) t ^ 2024 + 1 dt x ^ 2

JEE Main 2024 Solution
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46

Let f: [- (π)/(2), (π)/(2)] → R be a differentiable function such that f(0) = (1)/(2) , If _ x → 0 x ∫ _ 0 ^ x f ( t ) dt e ^ x ^ 2 - 1 = α , then 8 α ^ 2 is equal to :

JEE Main 2024 Solution
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47

Let the slope of the line 45x + 5y + 3 = 0 be 27 r _ 1 + 9 r _ 2 2 for some r _ 1 , r _ 2 ∈ R . Then _ x → 3 ( ∫ _ 3 ^ x 8 t ^ 2 3 r _ 2 x 2 - r _ 2 x ^ 2 - r _ 1 x ^ 3 - 3x dt)

JEE Main 2024 Solution
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48

_ x → (π)/(2) ((1)/( ( x - (π)/(2))2) ∫ _ x3 ^ ((π)/(2))3 cos ((1)/(t3)) dt) is equal to

JEE Main 2024 Solution
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49

If _ x → 0 3 + + + _ e ( 1 - x ) 3 ^ 2 x = (1)/(3) , then 2α - β is equal to :

JEE Main 2024 Solution
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50

If a = _ x → 0 1 + 1 + x ^ 4 - 2 x ^ 4 and b = _ x → 0 ^ 2 x 2 - 1 + cosx , then the value of a b ^ 3 is :

JEE Main 2024 Solution
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51

Let f: (0, 1) → ℝ be the function defined as f(x) = n if x ∈ [ (1)/(n + 1), (1)/(n) ) where n ∈ ℕ . Let g: (0, 1) → ℝ be a function such that ∫ _ x ^ 2 ^ x (1 - t)/(t) dt < g(x) <

JEE Advanced 2023 Solution
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52

If _ x → 0 e ^ ax - cos ( bx ) - cx e ^ - cx 2 1 - cos ( 2x ) = 17 , then 5 a ^ 2 + b ^ 2 is equal to

JEE Main 2023 Solution
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53

If α > β > 0 are the roots of the equation a x ^ 2 + bx + 1 = 0 , and _ x → (1)/(α) ( 1 - cos( x ^ 2 + bx + a) 2 ( 1 - ) ^ 2 )(1)/(2) = (1)/(k)((1)/(β) - (1)/(α)) , then k is

JEE Main 2023 Solution
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54

_ x → 0 (( 1 - ^ 2 ( 3x ) ^ 3 ( 4x ) )( ^ 3 ( 4x ) ( _ e (2x + 1)) ^ 5 )) is equal to

JEE Main 2023 Solution
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55

_ n → ∞ \ (2(1)/(2) - 2(1)/(3))(2(1)/(2) - 2(1)/(5)) . . . . (2(1)/(2) - 2(1)/(2n + 1))\ is equal to

JEE Main 2023 Solution
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56

_ x → ∞ ( 3x + 1 + 3x - 1 ) ^ 6 + ( 3x + 1 - 3x - 1 ) ^ 6 (x + x ^ 2 - 1 ) ^ 6 + (x - x ^ 2 - 1 ) ^ 6 x ^ 3

JEE Main 2023 Solution
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57

Let f, g and h be the real valued functions defined on ℝ as f(x) = \ cases (x)/(|x|), & x ≠ 0 1, & x = 0 cases , g(x) = \ cases (sin(x + 1))/((x + 1)), & x ≠ - 1 1, & x = - 1

JEE Main 2023 Solution
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58

Let x = 2 be a root of the equation x ^ 2 + px + q = 0 and f(x) = \ cases 1 - cos( x ^ 2 - 4px + q ^ 2 + 8q + 16) (x - 2p) ^ 4 , & x ≠ 2p 0, & x = 2p cases ). Then _ x → 2 p ^ +

JEE Main 2023 Solution
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59

The value of _ n → ∞ 1 + 2 - 3 + 4 + 5 - 6 + … + ( 3n - 2 ) + ( 3n - 1 ) - 3n 2 n ^ 4 + 4n + 3 - n ^ 4 + 5n + 4 is

JEE Main 2023 Solution
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60

The set of values of a for which _ x → a ([x - 5] - [2x + 2]) = 0 , where, [ζ] denotes the greatest integer less than or equal to ζ is equal to

JEE Main 2023 Solution
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61

_ t → 0 (1 1 ^ 2 t + 2 1 ^ 2 t + 3 1 ^ 2 t . . . . . . n 1 ^ 2 t ) ^ ^ 2 t is equal to

JEE Main 2023 Solution
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62

If β = _ x → 0 e ^ x ^ 3 - (1 - x ^ 3 )(1)/(3) + ((1 - x ^ 2 )(1)/(2) - 1)sinx x ^ 2 x , then the value of 6β is

JEE Advanced 2022 Solution
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63

Let α be a positive real number. Let f: ℝ → ℝ and g: (α, ∞) → ℝ be the functions defined by f(x) = sin(( )/(12)) and g(x) = 2 _ e ( x - α ) _ e ( e ^ x - e ^ α ) . Then the value

JEE Advanced 2022 Solution
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64

If _ x → 0 α e ^ x + β e ^ - x + x ^ 2 x = (2)/(3) , where α, β, γ ∈ R , then which of the following is NOT correct?

JEE Main 2022 Solution
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65

_ x → 0 ( (x + 2cosx) ^ 3 + 2 (x + 2cosx) ^ 2 + 3sin(x + 2cosx) (x + 2) ^ 3 + 2 (x + 2) ^ 2 + 3sin(x + 2) )(100)/(x) is equal to

JEE Main 2022 Solution
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66

Let f: ℝ → ℝ be a function defined as f(x) = asin((π[x])/(2)) + [2 - x], a ∈ ℝ , where [t] is the greatest integer less than or equal to t . If _ x → - 1 f (x) exists, then the

JEE Main 2022 Solution
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67

Let β = _ x → 0 - ( e ^ 3x - 1) ( e ^ 3x - 1) for some α ∈ ℝ . Then the value of α + β is:

JEE Main 2022 Solution
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68

_ x → (π)/(4) 8 2 - (cosx + sinx) ^ 7 2 - 2 sin2x is equal to

JEE Main 2022 Solution
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69

If _ n → ∞ ( n ^ 2 - n - 1 + nα + β) = 0 then 8(α + β) is equal to

JEE Main 2022 Solution
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70

The value of _ x → 1 ( x ^ 2 - 1) ^ 2 ( ) x ^ 4 - 2 x ^ 3 + 2x - 1 is equal to:

JEE Main 2022 Solution
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71

If _ x → 1 ( sin(3 x ^ 2 - 4x + 1) - x ^ 2 + 1 2 x ^ 3 - 7 x ^ 2 + ax + b ) = - 2 , then the value of (a - b) is equal to

JEE Main 2022 Solution
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72

Let [t] denote the greatest integer ≤ t and \ t\ denote the fractional part of t . Then integral value of α for which the left hand limit of the function f(x) = [1 + x] + α ^ 2[x]

JEE Main 2022 Solution
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73

Let a be an integer such that _ x → 7 (18 - [1 - x])/([x - 3a]) exists, where [t] is greatest integer ≤ t . Then a is equal to

JEE Main 2022 Solution
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74

_ x → 0 cos ( sinx ) - cosx x ^ 4 is equal to

JEE Main 2022 Solution
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75

_ x → 1 2 sin( ^ - 1 x) - x 1 - tan( ^ - 1 x) is equal to

JEE Main 2022 Solution
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76

_ x → (π)/(2) ( ^ 2 x((2 ^ 2 x + 3sinx + 4)(1)/(2) - ( ^ 2 x + 6sinx + 2)(1)/(2))) is equal to

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77

Let f(x) be a polynomial function such that f(x) + f ^ ' (x) + f ^ ' ' (x) = x ^ 5 + 64 . Then, the value of _ x → 1 (f(x))/(x - 1) is equal to

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78

Let f ( x ) = x ^ 6 + 2 x ^ 4 + x ^ 3 + 2x + 3, x ∈ R . Then the natural number n for which _ x → 1 x ^ n f ( 1 ) - f ( x ) x - 1 = 44 is _____ .

JEE Main 2021 Solution
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79

If α = _ x → π / 4 ^ 3 x - tanx cos(x + (π)/(4)) and β = _ x → 0 (cosx) ^ cotx are the roots of the equation, a x ^ 2 + bx - 4 = 0, then the ordered pair (a, b) is :

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80

_ x → 0 ^ 2 (π ^ 4 x) x ^ 4 is equal to :

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81

If _ x → ∞ ( x ^ 2 - x + 1 - ax) = b , then the ordered pair ( a, b ) is:

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82

If α, β are the distinct roots of x ^ 2 + bx + c = 0, then _ x → β e ^ 2( x ^ 2 + bx + c) - 1 - 2( x ^ 2 + bx + c) ( x - β ) ^ 2 is equal to

JEE Main 2021 Solution
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83

_ x → 2 ( ∑ _ n = 1 ^ 9 x n ( n + 1 ) x ^ 2 + 2 ( 2n + 1 ) x + 4 ) is equal to :

JEE Main 2021 Solution
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84

The value of _ x → 0 ((x)/(1 - sinx8 - 1 + sinx8)) is equal to :

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85

Let f: R → R be a function such that f(2) = 4 and f ^ ' (2) = 1 . Then, the value of _ x → 2 x ^ 2 f(2) - 4f(x) x - 2 is equal to:

JEE Main 2021 Solution
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86

If _ x → 0 [ e ^ x - β _ e ( 1 + x ) + γ x ^ 2 e ^ - x x ^ 2 x ] = 10, α, β, γ ∈ R , then the value of α + β + γ is __________.

JEE Main 2021 Solution
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87

If the value of _ x → 0 (2 - cosx cos2x ) ^ ( x + 2 x ^ 2 ) is equal to e ^ a , then a is equal to_____.

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88

If _ x → 0 ^ - 1 x - ^ - 1 x 3 x ^ 3 is equal to L, then the value of ( 6L + 1 ) is

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89

The value of _ n → ∞ [r] + [2r] + . . . + [nr] n ^ 2 , where r is non-zero real number and [r] denotes the greatest integer less than or equal to r, is equal to :

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90

The value of the limit _ θ → 0 tan(π ^ 2 θ) sin(2π ^ 2 θ) is equal to :

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91

The value of _ x → 0 ^ + ^ - 1 (x - [ x ] ^ 2 ) · ^ - 1 (x - [ x ] ^ 2 ) x - x ^ 3 , where [x] denotes the greatest integer ≤ x is:

JEE Main 2021 Solution
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92

If _ x → 0 a e ^ x - bcosx + c e ^ - x xsinx = 2 , then a + b + c is equal to ________.

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93

Let f(x) be a differentiable function at x = a with f ^ ' (a) = 2 and f(a) = 4 . Then _ x → a (xf(a) - af(x))/(x - a) equals:

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94

The value of _ h → 0 \ 3 sin((π)/(6) + h) - cos((π)/(6) + h) 3 h( 3 cosh - sinh) \ is :

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95

If _ x → 0 ax - ( e ^ 4x - 1) ax( e ^ 4x - 1) exists and is equal to b , then the value of a - 2b is ___ .

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96

_ n → ∞ (1 + 1 + (1)/(2) + … … + (1)/(n) n ^ 2 ) ^ n is equal to

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97

The value of the limit _ x → (π)/(2) 4 2 (sin3x + sinx) (2sin2xsin(3x)/(2) + cos(5x)/(2)) - ( 2 + 2 cos2x + cos(3x)/(2)) is _________

JEE Advanced 2020 Solution
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98

Let e denote the base of the natural logarithm. The value of the real number a for which the right-hand limit _ x → 0 ^ + (1 - x)(1)/(χ) - e ^ - 1 x ^ a is equal to a non-zero

JEE Advanced 2020 Solution
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99

_ x → 0 x( e ^ ( 1 + x ^ 2 + x ^ 4 - 1) / x - 1) 1 + x ^ 2 + x ^ 4 - 1

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100

If α is the positive root of the equation, p(x) = x ^ 2 - x - 2 = 0 , then _ x → α ^ + 1 - cosp(x) x + α - 4 is equal to

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101

_ x → a (a + 2x\ right)(1)/(3) -(3x\ right)(1)/(3) (3a + x\ right)(1)/(3) -(4x\ right) dfrac 1 3 (a ≠ 0) & is equal to:

JEE Main 2020 Solution
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102

Let [t] denote the greatest integer ≤ t . If λεR - \ 0, 1\ , _ x → 0 |(1 - x + |x|)/(λ - x + [x])| = L , then L is equal to

JEE Main 2020 Solution
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103

If _ x → 0 \ 1 x ^ 8 (1 - cos x ^ 2 2 - cos x ^ 2 4 + cos x ^ 2 2 cos x ^ 2 4 )\ = 2 ^ - k then the value of k is

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104

_ x → 0 (tan((π)/(4) + x)) ^ 1 / x is equal to

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105

If _ x → 1 x + x ^ 2 + x ^ 3 + . . . + x ^ n - n x - 1 = 820, (n ∈ N) then the value of n is equal to....

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106

_ x → 0 ( 3 x ^ 2 + 2 7 x ^ 2 + 2 ) 1 x ^ 2 is equal to

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107

_ x → 2 3 ^ x + 3 ^ 3 - x - 12 3 ^ - (x)/(2) - 3 ^ 1 - x is equal to

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108

If f(x) is a polynomial satisfying f(x)f((1)/(x)) = f(x) + f((1)/(x)) and f(2) > 1, then _ x → 1 f (x) is

NTA Abhyas JEE Main 2020 Solution
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109

If _ x → 0 ⁡ ^ - 1 ⁡ x - ^ - 1 ⁡ x x ^ 3 equals L , then the value of ( 4L + 1 ) is

NTA Abhyas JEE Main 2020 Solution
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110

_ x → 2 3 ^ x + 3 ^ 3 - x - 12 3 ^ - (x)/(2) - 3 ^ 1 - x is equal to

NTA Abhyas JEE Main 2020 Solution
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111

& If p,q,r,s > 0, then _ x → ∞ ( p(1)/(x) + q(1)/(x) + r(1)/(x) + s(1)/(x) 4 )^ 3 x is equal to

NTA Abhyas JEE Main 2020 Solution
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112

The value of _ x → 0 x^ 6000 - (sin x)6000 x^ 2 (sin x)6000 & is

NTA Abhyas JEE Main 2020 Solution
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113

The value of _ x → ∞ ⁡ ((3x - 4)/(3x + 2)) ^ (x + 1)/(3) is equal to

NTA Abhyas JEE Main 2020 Solution
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114

If f(x) = \ cases g(x) – 1 x – 1 ; & x ≠ 1 1; & x = 1 cases ) and g^ &#39; (1) = 2, g (1) = 1 , then _ x → 1 ⁡ f (x) is equal to

NTA Abhyas JEE Main 2020 Solution
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115

The value of _ x → 0 ( 1 + x + x^ 2 ) + ( 1 - x + x^ 2 ) secx - cosx & is equal to

NTA Abhyas JEE Main 2020 Solution
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116

_ x → 0 ⁡ (1 + x) x^ 2 + (x - 1)/(x) =

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117

_ x → (π)/(2) [1 - tan((x)/(2))][1 - sinx] [1 + tan((x)/(2))] [π - 2x] ^ 3 is equal to

NTA Abhyas JEE Main 2020 Solution
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118

If _ x → 0 ( ( a - n ) nx - tan x)sinnx x2 = 0, where n is a non zero real number, then a is equal to

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119

The value of _ x → ∞ ⁡ 2 (x) ^ 1 / 2 + 3 (x) ^ 1 / 3 + 4 (x) ^ 1 / 4 +..... + (x) ^ 1 / n (2x - 3) ^ 1 / 2 + (2x - 3) ^ 1 / 3 +.... + (2x - 3) ^ 1 / n is

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120

The value of _ x → 0 1 + sin x - cos x + (1 - x) x · ^ 2 x & is

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121

The value of _ n → ∞ ⁡ 3.2 ^ n + 1 - 4.5 ^ n + 1 5.2 ^ n + 7.5 ^ n is equal to

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122

The value of _ x → π tan ⁡ (π ^ 2 ⁡ x ) ^ 2 ⁡ x is equal to

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123

The value of _ x → 0 ^ - 2 ^ (1)/(x) + 2 ^ (3)/(x) 3( 2 ^ (1)/(x) ) + 5( 2 ^ (3)/(x) ) is

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124

The value of _ x → 0 ( (sin ⁡ 5x + cos ⁡ 5x))/(tan ⁡ 3x) is equal to

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125

The value of _ x → 0 (sin ⁡ x)/(3)[(5)/(x)]is equal to (where, [.] represents the greatest integer function)

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126

The value of _ x → 0 tan^ 2 3x 5 - 4 + secx & is equal to

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127

The value of _ x → 1 ^ - π - 4tan^ - 1 x 1 - x is equal to

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128

The value of _ x → ∞ (ln ⁡ x) ^ 2 2 + 3x^ 2 is equal to

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129

The value of _ x → 0 xcot(4x) tan^ 2 (3x)cot^ 2 (6x) is equal to

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130

The value of _ x → 0 e^ - (x2)/(2) - cos ⁡ x x^ 3 tan ⁡ x is equal to

NTA Abhyas JEE Main 2020 Solution
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131

The value of _ x → 1 ^ + ∫ _ 1 ^ x |t - 1|dt sin ⁡ ( x - 1 ) is equal to

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132

If _ x → 0 ( 1 + px + qx^ 2 ) ^ cosecx = e^ 5 , then

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133

The value of _ x → 0 (1 - 2 x) (3 + x) x 4 x & is equal to&

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134

If _ x → 0 (sin ⁡ 2x - asin ⁡ x)/(x3) exists finitely, then the value of a is

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135

The value of _ x → 0 ⁡ 1 x ^ 18 (1 - cos ⁡ ( x ^ 3 3 ) - cos ⁡ ( x ^ 6 6 ) + cos ⁡ ( x ^ 3 3 ) ⋅ cos ⁡ ( x ^ 6 6 )) is λ ^ 2 , then the value of 900λ is equal to (here, λ > 0 )

NTA Abhyas JEE Main 2020 Solution
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136

If _ x → ∞ a e ^ x + bcosx + c + dx xsi n ^ 2 x = 3 , then the value of 272 abd c ^ 3 is equal to

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137

The value of _ x → 0 ^ - 4(2 + (3)/(x)) + 5 ( 2 ^ (1)/(x) ) 2(1 + (6)/(x)) + 6 ( 2 ^ (1)/(x) ) is equal to

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138

The value of _ x → 0 sec ⁡ x - (sec ⁡ x) ^ secx 1 - sec ⁡ x + ln ⁡ (sec ⁡ x) is equal to

NTA Abhyas JEE Main 2020 Solution
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139

The value of _ n → ∞ ( cos ⁡ xcos dfrac x 2 cos(x)/(4) . . . cos x 2 ^ n ) is equal to

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140

The value of _ x → (π)/(4) ⁡ (sin ⁡ 2x) ^ ^ 2 ⁡ 2x is equal to

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141

If _ x → 0 x(1 + acos ⁡ x) - bsin ⁡ x x ^ 3 = 1 , then the value of ab is equal to

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142

If L = _ x → (π)/(4) (1 - tanx)(1 - sin2x) (1 + tanx) (π - 4x) ^ 3 , then the value of 40L is equal to

NTA Abhyas JEE Main 2020 Solution
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143

The value of _ x → 0 1 - cos^ 3 (sin ⁡ x) sin ⁡ xsin(sin ⁡ x)cos(sin ⁡ x) is equal to

NTA Abhyas JEE Main 2020 Solution
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144

The value of _ x → 1 xtan\ x\ x - 1 ~is equal to (where \ x\ denotes the fractional part of x )

NTA Abhyas JEE Main 2020 Solution
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145

The value of _ x → 0 (sec ⁡ x + tan ⁡ x) ^ (1)/(x) is equal to

NTA Abhyas JEE Main 2020 Solution
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146

The value of _ x → (π)/(3) 2 - 3 sin ⁡ x - cos ⁡ x (3x - π) ^ 2 is equal to the reciprocal of the number

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147

The value of _ n → ∞ [x] + [ 2 ^ 2 x] + [ 3 ^ 2 x] +..... + [n^ 2 x] 1 ^ 2 + 2 ^ 2 + 3 ^ 2 +.... + n^ 2 is equal to (where [x] represents the greatest integer part of x )

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148

The value of _ x → ∞ e ^ x + 1 log( x ^ 3 e ^ - x + 1) si n ^ 3 (2x) is equal to (Use e = 2.7 )

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149

The value of _ x → 0 ln ⁡ (1 + 2x + 4x^ 2 ) + ln ⁡ (1 - 2x + 4x^ 2 ) sec ⁡ x - cos ⁡ x & is equal to

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150

The value of _ x → π sin(2 ^ 2 x) tan( ^ 2 x) is equal to

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151

The value of _ x → - ∞ x^ 2 tan((1)/(x)) 4x^ 2 - x + 1 is equal to

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152

Let F: R → R be a function. We say that f has: PROPERTY 1 if _ h → 0 ⁡ f(h) - f(0) |h| exists and is finite, and PROPERTY 2 if _ h → 0 ⁡ f(h) - f(0) h ^ 2 exists and is finite.

JEE Advanced 2019 Solution
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153

For a ∈ R, |a| > 1, let _ n → ∞ ⁡ ( 1 + 23 + … + n3 n ^ 7 / 3 ( 1 (an + 1) ^ 2 + 1 (an + 2) ^ 2 + … + 1 (an + n) ^ 2 ) ) = 54 . Then the possible value(s) of a is/are:

JEE Advanced 2019 Solution
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154

_ x → 0 x + 2sinx x ^ 2 + 2sinx + 1 - ^ 2 x - x + 1 is

JEE Main 2019 Solution
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155

If _ x → 1 x ^ 2 - ax + b x - 1 = 5, then a + b is equal to:

JEE Main 2019 Solution
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156

If _ x → 1 x ^ 4 - 1 x - 1 = _ x → k x ^ 3 - k ^ 3 x ^ 2 - k ^ 2 , then k is

JEE Main 2019 Solution
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157

If f(x) = [x] - [(x)/(4)], x ∈ R, where [x] denotes the greatest integer function, then:

JEE Main 2019 Solution
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158

Let f: R → R be a differentiable function satisfying f ^ ' (3) + f ^ ' (2) = 0 . Then _ x → 0 ((1 + f(3 + x) - f(3))/(1 + f(2 - x) - f(2))) ^ (1)/(x) is equal to

JEE Main 2019 Solution
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159

_ x → 0 ^ 2 x 2 - 1 + cosx equals

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160

_ x → 1 ^ - π - 2 ^ - 1 x 1 - x is equal to

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161

_ x → (π)/(4) co t ^ 3 x - tanx cos(x + (π)/(4)) is

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162

_ x arrow 0 x (4 x) ^ 2 x ^ 2 (2 x) is equal to:

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163

Let [x] denote the greatest integer less than or equal to X . Then : _ x arrow 0 (π ^ 2 x)+(|x|- (x[x]))^ 2 x^ 2

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164

For each t ∈ R, let [t] be the greatest integer less than or equal to t . Then, _ x → 1 ^ + ((1 - |x| + sin|1 - x|)sin([1 - x](π)/(2)))/(|1 - x|[1 - x])

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165

For each x ∈ R , let [x] be the greatest integer less than or equal to x . Then _ x → 0 ^ - (x([x] + |x|)sin ⁡ [x])/(|x|) is equal to

JEE Main 2019 Solution
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166

The value of _ y → 0 1 + 1 + y ^ 4 - 2 y ^ 4

JEE Main 2019 Solution
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167

For each positive integer n , let y _ n = (1)/(n) ( ( n + 1 )( n + 2 )...( n + n ) )(1)/(n) . If _ n → ∞ ⁡ y _ n = L, then the value of [L] (where [x] is the greatest integer less

JEE Advanced 2018 Solution
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168

_ x → 0 (( 27 + x )(1)/(3) - 3)/(9 - ( 27 + x )(2)/(3)) equals

JEE Main 2018 Solution
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169

_ x arrow 0 (x 2 x-2 x x)/((1- 2 x)^2) equals.

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170

For each t ∈ R, let [t] be the greatest integer less than or equal to t . Then _ x → 0 ^ + x([(1)/(x)] + [(2)/(x)] + … + [(15)/(x)])

JEE Main 2018 Solution
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171

Let f(x) = (1 - x ( 1 + |1 - x| ))/(| 1 - x |)cos ⁡ ((1)/(1 - x))forx ≠ 1, then

JEE Advanced 2017 Solution
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172

_ x → 3 ⁡ 3x - 3 2x - 4 - 2 is equal to

JEE Main 2017 Solution
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173

_ x → (π)/(2) cotx - cosx (π - 2x) ^ 3 equals

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174

Let f(x) = _ n → ∞ ⁡ ( n ^ n (x + n)(x + (n)/(2)) … . . (x + (n)/(n)) n ! ( x ^ 2 + n ^ 2 )( x ^ 2 + n ^ 2 4 ) … . . ( x ^ 2 + n ^ 2 n ^ 2 ) ) ^ (x)/(n) , for all x > 0 . Then

JEE Advanced 2016 Solution
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175

Let f: ℝ → (0, ∞) and g: ℝ → ℝ be twice differentiable functions such that f ^ ″ and g ^ ″ are continuous functions on ℝ . Suppose f ^ ′ ( 2 ) = g( 2 ) = 0, f ^ ″ ( 2 ) ≠ 0 and g

JEE Advanced 2016 Solution
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176

Let α, β ∈ R be such that _ x → 0 ⁡ x ^ 2 sin ⁡ ( ) - sin ⁡ x = 1 . Then 6(α + β) equals

JEE Advanced 2016 Solution
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177

_ x → 0 ⁡ (1 - cos ⁡ 2x) ^ 2 2xtan ⁡ x - xtan ⁡ 2x is

JEE Main 2016 Solution
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178

If f(x) is a differentiable function in the interval (0, ∞) such that f(1) = 1 and _ t → x ⁡ t ^ 2 f(x) - x ^ 2 f(t) t - x = 1, for each x > 0, then f((3)/(2)) is equal to

JEE Main 2016 Solution
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179

If _ x → ∞ ⁡ (1 + (a)/(x) - 4 x ^ 2 ) ^ 2x = e ^ 3 , then a is equal to

JEE Main 2016 Solution
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180

_ n → ∞ ( (n + 1)(n + 2) … . 3n n ^ 2n )(1)/(n) is equal to

JEE Main 2016 Solution
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181

Let P = _ x → 0 ^ + (1 + ^ 2 x )(1)/(2x) , then logP is equal to

JEE Main 2016 Solution
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182

Let f: ℝ → ℝ be a continuous odd function, which vanishes exactly at one point and f(1) = (1)/(2) . Suppose that F(x) = ∫ _ - 1 ^ x f ( t )dt for all x ∈ [- 1, 2] and G(x) = ∫ _

JEE Advanced 2015 Solution
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183

Let m and n be two positive integers greater than 1. If _ α → 0 ⁡ ( e ^ cos ⁡ ( α ^ n ) - e α ^ m ) = - ((e)/(2)) then the value of (m)/(n) is

JEE Advanced 2015 Solution
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184

_ x → 0 ⁡ e ^ x ^ 2 - cos ⁡ x ^ 2 ⁡ x is equal to

JEE Main 2015 Solution
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185

_ x → 0 ((1 - cos 2x)(3 + cos x))/(x tan 4x) =

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186

The largest value of the non - negative integer a for which _ x → 1 ⁡ \ (- ax + sin ⁡ (x - 1) + a)/(x + sin ⁡ (x - 1) - 1)\ ^ 1 - x 1 - x = (1)/(4) is _________

JEE Advanced 2014 Solution
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187

If _ x arrow 2 (x-2\ x^2+k+2 x-2 k\ . x^2-4 x+4 =5 , then k is equal to:

JEE Main 2014 Solution
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188

If f(x) is continuous and f((9)/(2)) = (2)/(9), then _ x → 0 f( 1 - cos3x x ^ 2 ) equals to

JEE Main 2014 Solution
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189

_ x → 0 sin( π cos ^ 2 x) x ^ 2 is equal to

JEE Main 2014 Solution
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190

The value of _ x arrow 0 (1)/(x)[ ^ -1 ((x+1)/(2 x+1))-(π)/(4)] is :

JEE Main 2013 Solution
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191

The value of _ x → 0 ((1 - cos2x)(3 + cosx))/(xtan4x) is equal to

JEE Main 2013 Solution
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192

Let α(a) and β(a) be the roots of the equation ( [3] 1+a -1) x^ 2 +( 1+a -1) x+( [6] 1+a -1)=0 where a >-1 . Then _ a arrow 0^ + α(a) and _ x arrow 0^ + β(a) are

JEE Advanced 2012 Solution
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193

If _ x arrow ∞ ( x^ 2 +x+1 x+1 -a x-b)=4 , then

JEE Advanced 2012 Solution
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194

_ x arrow 0 ( (π ^2 x))/(x^2) equals

JEE Main 2012 Solution
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195

If f(x)=3 x^ 10 -7 x^8+5 x^6-21 x^3+3 x^2-7 , then _ α arrow 0 (f(1-α)-f(1))/(α^3+3 α) is

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196

_ x arrow 0 ((x- x)/(x)) ((1)/(x))

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197

If _ x arrow 0 [1+x (1+b^2)]^ 1 / x =2 b ^2 θ b>0 and θ ∈(-π, π] , then the value of θ is

JEE Advanced 2011 Solution
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198

_ x arrow 2 ( 1- \ 2 (x-2)\ x-2 )

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199

The value of _ x arrow 0 (1)/(x^3) ∫_0^x (t (1+t))/(t^4+4) d t is

JEE Advanced 2010 Solution
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200

Let f: R arrow R be a positive increasing function with _ x arrow ∞ (f(3 x))/(f(x))=1 . Then _ x arrow ∞ (f(2 x))/(f(x))=

JEE Main 2010 Solution
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