99 Percentile Qs Bank for JEE MainMathematicsLimits
lim x → 0 l n 1 + x x 2 + x - 1 x =
Options
- A∞
- B1 2
- C- 1 2
- D1
Correct answer
B. 1 2
Step-by-step solution
lim x → 0 l n 1 + x + x 2 - x x 2 using expansion, we know, l n 1 + x = x - x 2 2 + x 3 3 … … ⇒ lim x → 0 x - x 2 2 + . . . . + x 2 - x x 2 = 1 2