JEE Main2016ChemistryGeneral Principles and Processes of Isolation of MetalsActual
The plot shows the variation of - ln ⁡ K P Versus temperature for the two reactions. M s + 1 2 O 2 g → M O ( s ) and C s + 1 2 O 2 g → C O ( s ) Identify the correct statement:
Options
- AAt T < 1200   K , oxidation of carbon is unfavourable
- BOxidation of carbon is favourable at all temperatures
- CAt T < 1200   K , the reaction M O s + C s → M s + C O ( g ) is spontaneous
- DAt T > 1200   K , carbon will reduce MO s   to   M s .
Correct answer
C. At T < 1200   K , the reaction M O s + C s → M s + C O ( g ) is spontaneous
Step-by-step solution
Δ G = Δ G 0 + R T ln Q At Equilibrium Δ G = 0    &   Q = K ∆ G o = - R T ln ⁡ K p ∴- ln ⁡ K p = ∆ G o R T ∆ G o ∝ Temperature. At high temperature ∆ G o value is very high so non-feasible or non-spontaneous process takes place.