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Let S be the set of all real numbers. Then, the relation R = a , b : 1 + a b > 0 on S is

Options

  1. Areflexive and symmetric but not transitive
  2. Breflexive and transitive but not symmetric
  3. Creflexive, transitive and symmetric
  4. DNone of the above

Correct answer

A. reflexive and symmetric but not transitive

Step-by-step solution

R = a , b : 1 + a b > 0 (i) ( 1 , 1 ) ∈ R (ii) ( 1 , 2 ) ∈ R ⇒ ( 2 , 1 ) ∈ R (iii) ( 1 , 2 ) ∈ R and ( 2 , 3 ) ∈ R ⇒ ( 1 , 3 ) ∈ R It is clear that the given relation on S is reflexive, symmetric but not transitive.

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