99 Percentile Qs Bank for JEE MainMathematicsStraight Lines
The combined equation of the three sides of a triangle is (x^2-y^2 )(2 x+3 y-6)=0 . If the point (0, ) lies in the interior of this triangle, then
Options
- A-2 < < 0
- B-2 < < 2
- C0 < < 2
- D2
Correct answer
C. 0 < < 2
Step-by-step solution
The sides of a triangle are given by (x^2-y^2 )(2 x+3 y-6)=0 or x-y=0, x+y=0,2 x+3 y-6=0 We observe that the point (0, ) moves on x=0 . Thus, the value of lies between 0 < < 2 .