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99 Percentile Qs Bank for JEE MainMathematicsThree Dimensional Geometry

The equation of line equally inclined with the positivie co-ordinate axes and passing through ( − 3 , 2 , − 5 ) is

Options

  1. Ax + 3 1 = y - 2 1 = z + 5 1
  2. Bx + 3 - 1 = y - 2 1 = 5 + z - 1
  3. Cx + 3 - 1 = y - 2 1 = z + 5 1
  4. Dx + 3 - 2 = 2 - y 1 = z + 5 - 1

Correct answer

A. x + 3 1 = y - 2 1 = z + 5 1

Step-by-step solution

Equation of line passing through x 1 , y 1 , z 1 and having d . c . s . l , m , n is x - x 1 l = y - y 1 m = z - z 1 n Here ( x 1 , y 1 , z 1 ) ≡ - 3 , 2 , - 5 Also line is equally inclined with the positive co-ordinate axes. ∴ l = 1 , m = 1 , n = 1 ∴ Equation of line is x + 3 1 = y - 2 1 = z + 5 1

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