99 Percentile Qs Bank for JEE MainMathematicsTrigonometric Equations
If 5 x+12 y=13 , then the maximum value of 5 x+12 y is :
Options
- A12
- B120
- C20
- D13
Correct answer
B. 120
Step-by-step solution
5 x+12 y=13 (5 x+12 y)^2=169 (5 x+12 y)^2+(5 x+12 y)^2 (13)^2+(5 x+12 y)^2=25+144+120( x y+ x y) (5 x+12 y)^2=120 (x-y) -1 (x-y) 1 Maximum value of 5 x+12 y= 120