Grignard reagent RMgBr ( P ) reacts with water and forms a gas (Q). One gram of Q occupies 1.4 dm ³ at STP. (P) on reaction with dry ice in dry ether followed by H ₃ O ⁺ forms a compound (Z). 0.1 mole of (Z) will weigh _ _ _ _ g. (Nearest integer)

Step-by-step solution

Grignard reagent RMgBr reacts with water to produce gas Q. One gram of Q occupies 1.4 L at STP. Moles of Q = 1.4/22.4 = 0.0625 mol, so molar mass = 1/0.0625 = 16 g/mol, identifying Q as CH₄. Thus P = CH₃MgBr. When P reacts with dry ice: CH ₃ MgBr + CO ₂ CH ₃ COOMgBr . Upon treatment with H₃O⁺, this gives Z = CH₃COOH (acetic acid). Molar mass of Z = 60 g/mol. Mass of 0.1 mol = 0.1 × 60 = 6 g.