99 Percentile Qs Bank for JEE MainPhysicsCurrent Electricity
In the given electrical circuit, which one of the following equation is a correct equation?
Options
- AE 2 - i 2 r 2 - E 1 - i 1 r 1 = 0
- BE 1 - i 1 + i 2 R + i 1 r 1 = 0
- CE 1 - i 1 + i 2 R - i 1 r 1 = 0
- D- E 2 - i 1 + i 2 R + i 2 r 2 = 0
Correct answer
C. E 1 - i 1 + i 2 R - i 1 r 1 = 0
Step-by-step solution
The given circuit can be drawn as Applying Kirchhoff’s voltage law (KVL) in loop ABCD, we get - i 1 + i 2 R + E 2 - i 2 r 2 = 0 …. (i) Applying KVL in loop ABFEA, we get - i 1 + i 2 R - i 1 r 1 + E 1 = 0 ….. (ii) Applying KVL in Loop EFCDE, we get - E 1 + i 1 r 1 + E 2 - i 2 r 2 = 0 ….. (iii) From the given options, only option (c) satisfies Eq. (ii), hence it is the correct equation.