A uniform metal wire carries a current of 2 ~A when an ideal cell of 3.4 ~V is connected across it. The wire has mass 8.92 10⁻³ ~kg , density 8.92 10^3 kgm ⁻³ and resistivity 1.7 10⁻⁸ m . Then the length of the wire is

Step-by-step solution

Current, I =2 ~A Potential, V=3.4 v Using Ohm's law aligned & R = V I = 3.4 2 =1.7 & Volume = Mass Density & = 8.92 10⁻³ 8.92 10^3 =10⁻⁶ ~m ^3 & R = L VA L L = L ^2 ~V & ~L ^2= RV = 1.7 10⁻⁶ 1.7 10⁻⁸ aligned Length of the wire, L =10 ~m .