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In the circuit given below, if the bulb is to glow with maximum intensity, the value of ' R ' is (neglect internal resistance of the cell)

Options

  1. A1.25
  2. B4.5
  3. C6
  4. D8.5

Correct answer

A. 1.25

Step-by-step solution

Resistance of bulb, R= V^2 P = (1.5)^2 0.45 =5 P=i₁^2 R aligned & 0.45= i ₁ ^2 5 & i ₁=0.3 ~A aligned Apply KVL, We have aligned & -6+3 i 1.5=0 & i = 6-1.5 3 =1.5 ~A & 1.5= ( i - i ₁ ) R & 1.5=(1.5-0.3) R & R = 1.5 1.2 =1.25 aligned

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