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JEE Main 202528 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Haloalkanes and Haloarenes

JEE Main 2025 · 28 January · Morning Shift · Chemistry · Haloalkanes and Haloarenes

Consider the following sequence of reactions: 11.25 mg of...

Consider the following sequence of reactions: Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce __________ × 10^ -1 mg of product
11.25 mg of chlorobenzene will produce __________ ×10−1mg\times 10^{-1} \mathrm{mg} of product B . (Consider the reactions result in complete conversion.) [Given molar mass of C,H,O,N\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N} and Cl as 12,1,16,1412,1,16,14 and 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1} respectively]

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Step-by-step solution

Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce __________ × 10^ -1 mg of product
Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce __________ × 10^ -1 mg of product
11.25×10−3112.5=x×10−1×10−393x×10−1=93×0.1x=93mg\begin{aligned} & \frac{11.25 \times 10^{-3}}{112.5}=\frac{x \times 10^{-1} \times 10^{-3}}{93} \\ & x \times 10^{-1}=93 \times 0.1 \\ & x=93 \mathrm{mg}\end{aligned}
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