JEE Main
- Exam
- JEE Main
- Subject
- Physics
- Chapter
- Electromagnetic Waves
JEE Main · Physics · Electromagnetic Waves
Modified Ampere's circuital law stated by Maxwell is ( I =...
Modified Ampere's circuital law stated by Maxwell is conduction current, displacement current, and & is& permeability and permittivity of free space)
Options
- A{ε}_{0} \cdot {μ}_{0} \left[I + \dfrac{d{ϕ}_{E}}{dt}\right]&
- B{μ}_{0} \left[I + {ϵ}_{0} \dfrac{d{ϕ}_{E}}{dt}\right]&
- C{ε}_{0} \left[I + {μ}_{0} \dfrac{dϕE}{dt}\right]&
- D\dfrac{ϵ0}{\mu0} \left[I + \dfrac{dϕE}{dt}\right]$$
Correct answer
B. {μ}_{0} \left[I + {ϵ}_{0} \dfrac{d{ϕ}_{E}}{dt}\right]&
Step-by-step solution
The total current through the circuit will be the sum of the conduction current and the displacement current. Ampere's law has only conduction current but after Maxwell modification, displacement current is also added in it. The Maxwell-Ampere equation is given by,
∮ \overset{→}{B} \cdot d \overset{→}{l} = {μ}_{0} \left(I + {ε}_{0} \cdot \dfrac{d {ϕ}_{E}}{d t}\right).