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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main · Physics · Electromagnetic Waves

Let E_0 and B_0 denote the amplitude of electric and magnetic field...

Let E0\mathbf{E}_0 and B0\mathbf{B}_0 denote the amplitude of electric and magnetic field of a plane electromagnetic wave in air. The magnitude of the average momentum transferred per unit area and per unit time to a totally absorbing surface is

Options

  1. A12ε0E02\frac{1}{2} \varepsilon_0 E_0^2
  2. B12μ0B0\frac{1}{2} \mu_0 B_0
  3. Cε0E02\varepsilon_0 E_0^2
  4. D2B02μ02 \frac{B_0^2}{\mu_0}

Correct answer

A. 12ε0E02\frac{1}{2} \varepsilon_0 E_0^2

Step-by-step solution

Intensity of electromagnetic wave, I=12ε0E02c=\frac{1}{2} \varepsilon_0 E_0^2 c=\frac{1}{2} \frac{B_0^2 c}{\mu_0}where,where,B_0=electricfieldandelectric field andc=speedoflight.Now,momentumtransferperunitareaperunittime,whichisalsocalledradiationpressure.speed of light. Now, momentum transfer per unit area per unit time, which is also called radiation pressure.\begin{gathered}\frac{1}{A}\left(\frac{\Delta p}{\Delta t}\right)=\frac{I}{c}=\frac{\frac{1}{2} \varepsilon_0 E_0^2 c}{c}\\ \frac{I}{c}=\frac{1}{2} \varepsilon_0 E_0^2 \end{gathered} [where, Δp=\Delta p= momentum transferred, Δt=\Delta t= time and A=A= area.]
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