99 Percentile Qs Bank for JEE MainPhysicsElectromagnetic Waves
A large parallel plate capacitor, whose plates have an area of 1   m 2 and are separated from each other by 1   mm , is being charged at a rate of 25   V   s - 1 . If the dielectric between the plates has the dielectric constant 10 , then the displacement current at this instant is
Options
- A25 μ A
- B11 μ A
- C2.2 μ A
- D1.1 μ A
Correct answer
C. 2.2 μ A
Step-by-step solution
The capacity of a parallel plate capacitor is C = ε 0 K A d = ( 8.85 × 10 - 12 ) × 10 × 1 10 - 3 = 8.85 × 10 - 8   F The displacement current is i = d d t C V = C d V d t = 8 .85 × 10 - 8 × 25 i = 2 .2 × 10 - 6   A .