A large parallel plate capacitor, whose plates have an area of 1m^ 2 and are separated from each other by 1 mm, is being charged at a rate of 25Vs^ - 1 . If the dielectric between the plates has the dielectric constant

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Quantrex Academy · Accepted Answer

Correct answer: C. 2.2

The capacity of a parallel plate capacitor is&

C = \dfrac{{ε}_{0}KA}{d} = \dfrac{( 8.85 \times {10}^{- 12} ) \times 10 \times 1}{10- 3}

= 8.85 \times {10}^{- 8}F

The displacement current is

i = \dfrac{d}{dt}\left(CV\right) = C\dfrac{dV}{dt} = 8 .85 \times {10}^{- 8} \times 25

i = 2 .2 \times {10}^{- 6}A

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A large parallel plate capacitor, whose plates have an area of 1m^...

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