2 - Methyl propyl bromide reacts with C _ 2 H _ 5 O ^ - and gives ‘ A ’ whereas on reaction with C _ 2 H _ 5 OH it gives ‘ B ’ . The mechanism followed in these reactions and the products ‘ A ’ and ‘ B ’ respectively

Question

Quantrex Academy · Accepted Answer

Correct answer: A. S _ N 2, A = iso-butyl ethyl ether; S _ N 1, B = tert-butyl ethyl ether

The reaction between methyl propyl bromide and ${C}_{2}{H}_{5}{O}^{-}$ proceeds via an ${S}_{N}2$ (substitution nucleophilic bimolecular) mechanism. In this mechanism, the nucleophile attacks the carbon atom bearing the bromine (the electrophilic carbon) in a single step, leading to the displacement of the bromine atom.

2 - Methyl propyl bromide reacts with C _ 2 H _ 5 O ^ - and gives ‘ A ’ whereas on reaction with C _ 2 H _ 5 OH it

The reaction between methyl propyl bromide and ${C}_{2}{H}_{5}OH$ can proceed via either an ${S}_{N}1$ (substitution nucleophilic unimolecular). Here ${C}_{2}{H}_{5}OH$ is a weak nucleophile. During the reaction 1,2-hydrogen shift will occur and tert-butyl ethyl ether is formed.

2 - Methyl propyl bromide reacts with C _ 2 H _ 5 O ^ - and gives ‘ A ’ whereas on reaction with C _ 2 H _ 5 OH it

2 - Methyl propyl bromide reacts with C _ 2 H _ 5 O ^ - and gives ‘...

Options

Correct answer

Step-by-step solution

More from Haloalkanes and Haloarenes