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2 - Methyl propyl bromide reacts with C 2 H 5 O - and gives ‘ A ’ whereas on reaction with C 2 H 5 OH it gives ‘ B ’ . The mechanism followed in these reactions and the products ‘ A ’ and ‘ B ’ respectively are:

Options

  1. AS N 2 , A = iso-butyl ethyl ether; S N 1 , B = tert-butyl ethyl ether
  2. BS N 1 ,   A = tert-butyl ethyl ether; S N 1 ,   B = 2 - butyl ethyl ether
  3. CS N 2 ,   A = 2 - butyl ethyl ether; S N 2 ,   B = iso-butyl ethyl ether
  4. DS N 1 ,   A = tert-butyl ethyl ether; S N 2 ,   B = iso-butyl ethyl ether

Correct answer

A. S N 2 , A = iso-butyl ethyl ether; S N 1 , B = tert-butyl ethyl ether

Step-by-step solution

The reaction between methyl propyl bromide and C 2 H 5 O - proceeds via an S N 2 (substitution nucleophilic bimolecular) mechanism. In this mechanism, the nucleophile attacks the carbon atom bearing the bromine (the electrophilic carbon) in a single step, leading to the displacement of the bromine atom. The reaction between methyl propyl bromide and C 2 H 5 OH can proceed via either an S N 1 (substitution nucleophilic unimolecular). Here C 2 H 5 OH is a weak nucleophile. During the reaction 1,2-hydrogen shift will

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