99 Percentile Qs Bank for JEE MainPhysicsOscillations
A small sphere of radius r is placed as a concave surface of radius of curvature R a little away from the centre. When the sphere is released, it oscillates. Assuming, the oscillation to be simple harmonic motion and r< < R , then the time period is
Options
- A2 R g
- B2 3 R 2 g
- C2 2 R 3 g
- D2 R 2 g
Correct answer
A. 2 R g
Step-by-step solution
The motion of sphere is as shown in figure As, the sphere has simple harmonic motion on a curved surface, which is equivalent to the motion of pendulum. So, its time period is T=2 l g Here, l=R T=2 R g