Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainPhysicsOscillations

The displacement of a particle of mass 0 . 1   kg is, y = 0 . 05 sin 4 π 5 t + 0 . 4 (where all the quantities are in SI unit). Period of motion is 0 . 1   s . The total energy of the particle is,

Options

  1. A0 . 05 π 2   J
  2. B0 . 05   J
  3. C5 π 2   J
  4. D5   J

Correct answer

A. 0 . 05 π 2   J

Step-by-step solution

Given, the mass of the particle, m = 0 . 1   kg and the displacement, y = 0 . 05 sin 4 π 5 t + 0 . 4 and time period, T = 0 . 1   s . Now, comparing it with the equation of displacement of SHM , y = A sin ω t . It means, A = 0 . 005   m , ω = 20 π . Now, the formula of total energy is, T . E . = 1 2 m ω 2 A 2 = 1 2 × 0 . 1 × 20 π 2 × 0 . 005 2 = 0 . 05 π 2   J

Practice Oscillations on Quantrex Academy →

More from Oscillations

A tank contains two immiscible liquids of densities 6 and 2 . The higher density liquid is filled up to a height L/2 from the bottom. A thin rod of density and length L is fully im 2026The frequency of oscillation of a mass m suspended by a spring is v₁ . If the length of the spring is cut to half, the same mass oscillates with frequency v₂ . The value of v₂/v₁ i 2026A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and released. The frequency associated with the 2026A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x = A to x = A 2 is _______ sec. 2026Match List-I with List-II. List-I List-II A. ^2 t I. Periodic with time period T = but not simple harmonic motion (SHM) B. ^3(2 t) II. Periodic with time period T = 2 but Not SHM C 2026A uniform disc of radius R and mass M is free to oscillate about the axis A as shown in the figure. For small oscillations the time period is ______. ( g is acceleration due to gra 2026The velocity of a particle executing simple harmonic motion along x -axis is described as v^2 = 50 - x^2 , where x represents displacement. If the time period of motion is x 7 s, t 2026The equation of motion of a particle is given by x = a (50t + 3 ) cm. The particle will come to rest at time t₁ and it will have zero acceleration at time t₂ . The t₁ and t₂ respec 2026 Full Oscillations list All 99 Percentile Qs Bank for JEE Main PYQs