99 Percentile Qs Bank for JEE MainPhysicsOscillations
A particle executes simple harmonic motion according to the equation x(t)=A ^2( t) . If the time period of the SHM is 0.2 ~s , then the value of (in units of rad / s ) is
Options
- A2
- B10
- C5
- D2.5
Correct answer
C. 5
Step-by-step solution
Given that, the equation of SHM aligned x(t) & =A ^2( t) & =A [ 1- 2 t 2 ]= A 2 - A 2 2 t aligned We know that, general equation of SHM is But according to question, So, comparing Eqs. (i) and (ii), we get aligned & a₁= A 2 , a₂=- A 2 and =2 & = 2 = 2 2 T = (0.2) rad / s [Given, T=0.2 ~s ] aligned Hence, =5 rad / s