99 Percentile Qs Bank for JEE MainPhysicsOscillations
A horizontal spring executes S.H.M. with amplitude 'A 1 ', when mass ' m ₁ ^ " is attached to it. When it passes through mean position another mass ' m ₂ ' is placed on it. Both masses move together with amplitude ' A₂ '. Therefore A₂: A₁ is
Options
- A[ m ₂ ~m ₁+ m ₂ ]^ 1 / 2
- B[ m _ 1+ m ₂ ~m ₁ ]^ 1 / 2
- C[ m ₁ ~m ₁+ m ₂ ]^ 1 / 2
- D[ m _ 1+ m ₂ ~m ₂ ]^ 1 / 2
Correct answer
C. [ m ₁ ~m ₁+ m ₂ ]^ 1 / 2
Step-by-step solution
At mean position (f_ net =0 ) ( ) Applying conservation of momentum ( aligned & m ₁ v ₁= ( m ₁+ m ₂ ) v ₂ & ~m ₁ ₁ ~A ₁= ( m ₁+ m ₂ ) ₂ ~A ₂ & But ₁= k m₁ & ₂= k m₁+m₂ A₂ & m₁ k m₁ A₁= (m₁+m₂ ) k m₁+m₂ A₂ & A₁ A₂ = m₁+m₂ m₁ & A₂ A₁ = m₁ m₁+m₂ aligned )