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JEE Main 20207 JanuaryEvening Shift

Exam: JEE Main
Year: 2020
Date: 7 January
Shift: Evening Shift
Subject: Chemistry
Chapter: Haloalkanes and Haloarenes

JEE Main 2020 · 7 January · Evening Shift · Chemistry · Haloalkanes and Haloarenes

For the following reactions where, k _ s and k _ e , are...

For the following reactions

For the following reactions where, k _ s and k _ e , are respectively, the rate constants for substitution and

For the following reactions where, k _ s and k _ e , are respectively, the rate constants for substitution and

where,

For the following reactions where, k _ s and k _ e , are respectively, the rate constants for substitution and

{k}_{s}

and

{k}_{e}

, are respectively, the rate constants for substitution and elimination, and

\mu = \dfrac{{k}_{s}}{{k}_{e}}

, the correct option is ________

Options

A{\mu}_{B} > {\mu}_{A} $<em>and</em>$ {k}_{e}\left(A\right) > {k}_{e}\left(B\right)
B{\mu}_{A} > {\mu}_{B} $<em>and</em>$ {k}_{e}\left(B\right) > {k}_{e}\left(A\right)
C{\mu}_{B} > {\mu}_{A} $<em>and</em>$ {k}_{e}\left(B\right) > {k}_{e}\left(A\right)
D{\mu}_{A} > {\mu}_{B} $<em>and</em>$ {k}_{e}\left(A\right) > {k}_{e}\left(B\right)

Correct answer

B. {\mu}_{A} > {\mu}_{B} $<em>and</em>$ {k}_{e}\left(B\right) > {k}_{e}\left(A\right)

Step-by-step solution

For the following reactions where, k _ s and k _ e , are respectively, the rate constants for substitution and

(B) with more steric crowding forms elimination product compared to substitution

{\text{K}}_{\text{e}} ( \text{B} ) > {\text{K}}_{\text{e}} ( \text{A} ) {\mu}_{\text{B}} = \dfrac{{\text{K}}_{\text{s}} ( \text{B} )}{{\text{K}}_{\text{e}} ( \text{A} )} < {\mu}_{\text{A}} = \dfrac{{\text{K}}_{\text{s}} ( \text{A} )}{{\text{K}}_{\text{e}} ( \text{A} )}

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