Determine the velocity of the centre of mass for the system of particles depicted in the figure.

Step-by-step solution

Let the right direction be the positive x-axis and the upward direction be the positive y-axis. The total mass of the system is: M = 1.0 + 1.2 + 1.5 + 0.50 + 1.0 = 5.2 kg The total momentum in the x-direction is: P_x = -1.0(1.5 37^ ) + 0 - 1.5(1.0 37^ ) + 0.50(3.0) + 1.0(2.0 37^ ) Using 37^ = 0.8 , we get: P_x = -1.2 + 0 - 1.2 + 1.5 + 1.6 = 0.7 kg m/s The total momentum in the y-direction is: P_y = -1.0(1.5 37^ ) + 1.2(0.4) + 1.5(1.0 37^ ) + 0 - 1.0(2.0 37^ ) Using 37^ = 0.6 , we get: P_y = -0.9 + 0.48 + 0.9 + 0 -