A particle travels in a circle of radius 1.0 cm with a speed given by v = 2.0 t , where v is in cm/s and t is in seconds. Calculate the tangential acceleration of the particle at t = 1 s .

Step-by-step solution

The tangential acceleration of a particle in circular motion is given by the rate of change of its speed with respect to time. Given the speed v = 2.0 t , the tangential acceleration a_t is: a_t = dv dt a_t = d dt (2.0 t) = 2.0 cm/s ^2 Since the tangential acceleration is constant, its value at t = 1 s remains 2.0 cm/s ^2 .