A body slipping on a rough horizontal plane experiences a deceleration of 4.0 m/s ^2 . Determine the coefficient of kinetic friction between the block and the plane.

Step-by-step solution

When a body slips on a rough horizontal plane, the only horizontal force acting on it is the kinetic friction. The frictional force is given by f_k = _k N , where N = mg is the normal reaction. The deceleration a is given by Newton's second law: ma = _k mg a = _k g Given a = 4.0 m/s ^2 and taking g = 10 m/s ^2 : _k = a g = 4.0 10 = 0.4