A body of mass 2 kg is situated on a rough inclined plane of inclination 30^ . Determine the magnitude of the force parallel to the incline needed to make the block move up the incline. The coefficient of static friction is 0.2 .

Step-by-step solution

The force required to move the block up the rough inclined plane must overcome both the component of gravity along the incline and the maximum static friction. The component of gravity parallel to the incline is: F_g = mg The normal force is: N = mg The maximum static friction force is: f_s = _s N = _s mg The total force F required to move the block up the incline is: F = F_g + f_s = mg + _s mg Substituting m = 2 kg , = 30^ , _s = 0.2 , and g = 9.8 m/s ^2 : F = 2 9.8 30^ + 0.2 2 9.8 30^ F = 19.6 0.5 + 3.92 3 2 F =