Concepts Of Physics MCQ Edition [Volume 1]PhysicsNewton's Laws of Motion
A force F = -kx , where k = 15 N/m , acts on a particle of mass 0.3 kg . Determine the initial acceleration of the particle when it is released from the position x = 20 cm .
Options
- A50 m/s ^2
- B0.9 m/s ^2
- C10 m/s ^2
- D1000 m/s ^2
Correct answer
C. 10 m/s ^2
Step-by-step solution
Given k = 15 N/m , m = 0.3 kg , and x = 20 cm = 0.2 m . The magnitude of the restoring force acting on the particle is given by |F| = kx . Substituting the given values: |F| = 15 0.2 = 3 N The initial acceleration of the particle is a = |F| m . a = 3 0.3 = 10 m/s ^2