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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Newton's Laws of Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Newton's Laws of Motion

In addition to the force of gravity, a force F = v × A acts on a...

In addition to the force of gravity, a force F⃗=v⃗×A⃗\vec{F} = \vec{v} \times \vec{A} acts on a particle, where v⃗\vec{v} represents the particle's velocity and A⃗\vec{A} is a constant horizontal vector. Determine the minimum speed at which a particle of mass mm must be projected to ensure it travels undeflected at a constant velocity.

Options

  1. A2mgA\dfrac{2mg}{A}
  2. BmgAmgA
  3. CmgA\dfrac{mg}{A}
  4. DAmg\dfrac{A}{mg}

Correct answer

C. mgA\dfrac{mg}{A}

Step-by-step solution

For the particle to move undeflected at a constant velocity, the net force acting on it must be zero.

The forces acting on the particle are the gravitational force mg⃗m\vec{g} and the given force F⃗=v⃗×A⃗\vec{F} = \vec{v} \times \vec{A}.

Equating the net force to zero gives:

mg⃗+v⃗×A⃗=0m\vec{g} + \vec{v} \times \vec{A} = 0

v⃗×A⃗=−mg⃗\vec{v} \times \vec{A} = -m\vec{g}

Taking the magnitude on both sides yields:

vAsin⁡θ=mgv A \sin \theta = mg

where θ\theta is the angle between the velocity vector v⃗\vec{v} and the constant horizontal vector A⃗\vec{A}.

To minimize the speed vv, sin⁡θ\sin \theta must be maximized. The maximum value of sin⁡θ\sin \theta is 11, which occurs when θ=90∘\theta = 90^{{}^{{}^{\circ}}}.

Substituting sin⁡θ=1\sin \theta = 1 gives:

v_\min A = mg

v_\min = \dfrac{mg}{A}
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