Determine the tension in the string as shown in the figure. The pulleys and the string are light, while all surfaces are frictionless. Use g = 10 m/s ^2 .

Step-by-step solution

Let T be the tension in the string and a be the magnitude of acceleration of the blocks. For the hanging block of mass m₂ = 1 kg , the forces acting on it are the downward gravitational force m₂g and the upward tension T . Assuming it accelerates downwards with acceleration a , its equation of motion is: m₂g - T = m₂a 10 - T = 1 a (1) For the block on the horizontal surface of mass m₁ = 1 kg , the string is attached to its left side, passes around the left pulley, and then goes to the right pulley. When the hanging