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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Physics and Mathematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Physics and Mathematics

Based on the figure, determine the angle that the resultant of OA ,...

Based on the figure, determine the angle that the resultant of OA⃗\vec{OA}, BC⃗\vec{BC} and DE⃗\vec{DE} makes with the X-axis.
Based on the figure, determine the angle that the resultant of OA , BC and DE makes with the X-axis.

Options

  1. Atan⁡−1(0.76)\tan^{-1}(0.76)
  2. Btan⁡−1(1.73)\tan^{-1}(1.73)
  3. Ctan⁡−1(0.58)\tan^{-1}(0.58)
  4. Dtan⁡−1(1.32)\tan^{-1}(1.32)

Correct answer

D. tan⁡−1(1.32)\tan^{-1}(1.32)

Step-by-step solution

OA_x = 2.0 \cos 30^\{}^{{}^{\circ}} = 2.0 \times \dfrac{\sqrt{3}}{2} \approx 1.732 \text{ m}

OA_y = 2.0 \sin 30^\{}^{{}^{\circ}} = 2.0 \times \dfrac{1}{2} = 1.0 \text{ m}

BC_x = -1.5 \cos 60^\{}^{{}^{\circ}} = -1.5 \times \dfrac{1}{2} = -0.75 \text{ m}

BC_y = 1.5 \sin 60^\{}^{{}^{\circ}} = 1.5 \times \dfrac{\sqrt{3}}{2} \approx 1.299 \text{ m}

DEx=0 mDE_x = 0 \text{ m}

DEy=−1.0 mDE_y = -1.0 \text{ m}

Rx=1.732−0.75+0=0.982 mR_x = 1.732 - 0.75 + 0 = 0.982 \text{ m}

Ry=1.0+1.299−1.0=1.299 mR_y = 1.0 + 1.299 - 1.0 = 1.299 \text{ m}

tan⁡θ=RyRx=1.2990.982≈1.32\tan \theta = \dfrac{R_y}{R_x} = \dfrac{1.299}{0.982} \approx 1.32

θ=tan⁡−1(1.32)\theta = \tan^{-1}(1.32)
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