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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Physics and Mathematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Physics and Mathematics

Let a be a vector of magnitude 4.5 unit pointing due north....

Let a⃗\vec{a} be a vector of magnitude 4.54.5 unit pointing due north. Evaluate the vector 3a⃗3\vec{a}.

Options

  1. A13.513.5 unit due north
  2. B1.51.5 unit due north
  3. C13.513.5 unit due south
  4. D7.57.5 unit due north

Correct answer

A. 13.513.5 unit due north

Step-by-step solution

Given that the magnitude of vector a⃗\vec{a} is ∣a⃗∣=4.5|\vec{a}| = 4.5 units and its direction is due north.

When a vector is multiplied by a positive scalar, its magnitude is multiplied by the scalar and its direction remains unchanged.

The magnitude of the new vector 3a⃗3\vec{a} is 3×∣a⃗∣=3×4.5=13.53 \times |\vec{a}| = 3 \times 4.5 = 13.5 units.

Since 33 is a positive number, the direction of 3a⃗3\vec{a} is the same as a⃗\vec{a}, which is due north.

Thus, 3a⃗3\vec{a} is 13.513.5 units due north.
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