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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Physics and Mathematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Physics and Mathematics

Let a be a vector of magnitude 4.5 unit pointing due north....

Let a⃗\vec{a} be a vector of magnitude 4.54.5 unit pointing due north. Evaluate the vector −4a⃗-4\vec{a}.

Options

  1. A0.50.5 unit due south
  2. B8.58.5 unit due south
  3. C1818 unit due north
  4. D1818 unit due south

Correct answer

D. 1818 unit due south

Step-by-step solution

Given ∣a⃗∣=4.5|\vec{a}| = 4.5 units and its direction is due north.

The magnitude of the vector −4a⃗-4\vec{a} is ∣−4a⃗∣=∣−4∣∣a⃗∣=4×4.5=18|-4\vec{a}| = |-4| |\vec{a}| = 4 \times 4.5 = 18 units.

The negative sign indicates that the direction of −4a⃗-4\vec{a} is opposite to the direction of a⃗\vec{a}.

Since a⃗\vec{a} points due north, −4a⃗-4\vec{a} points due south.

Thus, −4a⃗-4\vec{a} is a vector of magnitude 1818 units pointing due south.
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