Two vectors possess magnitudes of 2 m and 3 m . The angle between them is 60^ . Determine the scalar product of the two vectors.

Step-by-step solution

Given | A | = 2 m and | B | = 3 m The angle between the vectors is = 60^ The scalar product of two vectors is given by A B = | A | | B | Substituting the given values: A B = 2 3 60^ A B = 6 1 2 = 3 m ^2