Two vectors possess magnitudes of 2 m and 3 m . The angle between them is 60^ . Determine the magnitude of their vector product.

Step-by-step solution

The magnitude of the vector product of two vectors A and B is given by | A B | = | A | | B | . Given | A | = 2 m , | B | = 3 m , and = 60^ . Substituting the values: | A B | = 2 3 60^ | A B | = 6 3 2 = 3 3 m ^2