A police jeep chases a culprit on a motorbike. The motorbike...

Speed of the motorbike, $v_m = 72 \text{ km/h} = 72 \times \dfrac{5}{18} = 20 \text{ m/s}$

Speed of the police jeep, $v_j = 90 \text{ km/h} = 90 \times \dfrac{5}{18} = 25 \text{ m/s}$

The jeep crosses the turning $10 \text{ s}$ after the motorbike. In this time, the distance covered by the motorbike is $d_0 = 20 \times 10 = 200 \text{ m}$

Relative speed of the jeep with respect to the motorbike is $v_{rel} = 25 - 20 = 5 \text{ m/s}$

Time taken by the jeep to catch up with the motorbike is $t = \dfrac{200}{5} = 40 \text{ s}$

Distance from the turning where the jeep catches the motorbike is $d = v_j \times t = 25 \times 40 = 1000 \text{ m} = 1 \text{ km}$