Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

Goli is a popular game in Indian villages, played with small glass...

Goli is a popular game in Indian villages, played with small glass balls known as golis. One player's goli is located at a distance of

2.0 \text{ m}

from the second player's goli. The second player must project his goli by keeping the thumb of the left hand at the position of his goli, holding the goli between his two middle fingers, and executing the throw. The second player wins if the projected goli strikes the first player's goli. Assuming the goli is projected horizontally from a height of

19.6 \text{ cm}

above the ground, determine the speed in m/s with which it must be projected to directly hit the stationary goli without falling on the ground earlier. (Take

g = 9.8 \text{ m/s}^2

)

Options

A $1$
B $50$
C $20$
D $10$

Correct answer

D. $10$

Step-by-step solution

The vertical motion of the goli is given by

h = \dfrac{1}{2} g t^2

.

Substituting the given values,

0.196 = \dfrac{1}{2} \times 9.8 \times t^2

t^2 = \dfrac{0.196}{4.9} = 0.04 \Rightarrow t = 0.2 \text{ s}

.

The horizontal motion is uniform, so the range is

R = u t

.

Substituting

R = 2.0 \text{ m}

and

t = 0.2 \text{ s}

, we get

2.0 = u \times 0.2

u = \dfrac{2.0}{0.2} = 10 \text{ m/s}

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